Attempts
|
Outcomes
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Multiples of 2&3
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1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
11.
12.
13.
14.
15.
16.
17.
18.
19.
20.
|
7+2=9
4+8=12
9+3=12
1+5= 6
6+1= 7
5+2= 7
6+1= 7
10+7=17
9+6=15
1+5=6
6+3= 9
2+1=3
1+3=4
6+5=11
1+6=7
9+9=18
6+8=14
1+2=3
7+7=14
7+3=10
|
Yes
Yes
Yes
Yes
No
No
No
No
Yes
Yes
Yes
Yes
Yes
No
No
Yes
Yes
Yes
Yes
Yes
|
Probability of getting a multiple of 2&3 is 14/20.
14/20= 70%
Walt: assign probabilities to simple events using fractions and percentages.
This week I was learning to assign probabilities to a game played with 2
10 sided dice. I played with Rebecca. Our predict was to get a multiple of two and three. We alternated rolling the dice. We did this twenty times. We recorded our score in the outcomes column. Of the 20 attempts we were successful 14 times. So the probability is 14/20 as a simple fraction and as a percentage it is 70%. Since we played similar games this week I have a better understanding of assigning probabilities. Next I ‘d like to learn to add and subtract integers.
1 comments:
Talofa Lava Natalia,
I like how your paragraph is, it has short sentences which make it easier to read. I also made a post about my maths which was linked with probability, like yours. Though I had to find out whether my outcome was a prime number. Would you like to do this again?
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